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Posted by: mdevos
on: July 15th, 2008

In an edge-colored digraph, we say that a subgraph is rainbow if all its edges have distinct colors, and monochromatic if all its edges have the same color.

Problem   Let $ G $ be a tournament with edges colored from a set of three colors. Is it true that $ G $ must have either a rainbow directed cycle of length three or a vertex $ v $ so that every other vertex can be reached from $ v $ by a monochromatic (directed) path?

This problem was raised in a paper by Sands, Sauer, and Woodrow [SSW] where they prove that every tournament with 2-colored edges has a vertex $ v $ so that every other vertex can be reached from $ v $ by a monochromatic path.

Galeana-Sanchez and Rojas-Monroy found a tournament on 6 vertices with 4-colored edges which has no rainbow triangle and does not have a vertex $ v $ which has monochromatic paths to all remaining vertices. However, the following generalization of the above conjecture looks plausible.

Problem   Does every edge-colored tournament have either a rainbow directed cycle or a vertex $ v $ so that every other vertex can be reached from $ v $ by a monochromatic path?

Bibliography

*[SSW] B. Sands, N. Sauer, R. Woodrow, On monochromatic paths in edge-coloured digraphs. J. Combin. Theory Ser. B 33 (1982), no. 3, 271--275. MathSciNet.


* indicates original appearance(s) of problem.

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