
Chain-meet-closed sets (Solved)
Let is a complete lattice. I will call a filter base a nonempty subset
of
such that
.
Definition A subset
of a complete lattice
is chain-meet-closed iff for every non-empty chain
we have
.




Conjecture A subset
of a complete lattice
is chain-meet-closed iff for every filter base
we have
.




The answer is yes. A proof is present in this online article.
Bibliography
*Victor Porton. Chain-meet-closed sets on complete lattices
* indicates original appearance(s) of problem.