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Diagonal Ramsey numbers
Let denote the
diagonal Ramsey number.
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Erdos offered $100 for a solution to the highlighted conjecture and $250 for a solution to the associated problem (these prizes are now provided by Graham).
Classic results of Erdos [E] and Erdos-Szekeres [ESz] give bounds on which show that if
exists, then it is in the interval
. Although these arguments are quite basic, little progress has been made in improving these bounds. The best known lower bound on
is due to Spencer [S] and the best known upper bound is due to Thomason [T]. They are as follows:
Gowers [G] has suggested that resolving these problems might require a rough structure theorem.
Bibliography
[E] P. Erdos, Some remarks on the theory of graphs, Bull. Amer. Math. Soc. 53 (1947), 292–294. MathSciNet
[ESz] P. Erdos and G. Szekeres, A combinatorial problem in geometry, Compositio Math. 2 (1935), 463–470.
[G] W. T. Gowers, Rough structure and classification, GAFA 2000 (Tel Aviv, 1999). Geom. Funct. Anal. 2000, Special Volume, Part I, 79--117. MathSciNet
[S] J. Spencer, Ramsey’s theorem—a new lower bound, J. Comb. Theory Ser. A 18 (1975), 108–115. MathSciNet
[T] A. Thomason, An upper bound for some Ramsey numbers, J. Graph Theory 12 (1988), 509–517. MathSciNet
* indicates original appearance(s) of problem.
Upper bound
The upper bound has been improved by David Conlon (to appear in Annals)
diagonal Ramsey numbers
Hi, My name is steve waterman.
re - diagonal Ramsey numbers
I have no proof of my conjectured formulas. However, the results are within the limits established in ALL cases. There is also a logic to these numbers as you will see.
http://www.watermanpolyhedron.com/RAMSEY.html
It is my belief that these values are indeed exact...that is, no bounds required, and thus an answer to this riddle - and as I also see it....only to be proven later. It is a big claim no doubt. I doubt that I will ever see a counter-example nor a single proof of say R(5,5) as long as I live. Lastly, knowing that these MAY INDEED BE the correct values...give us a chance to zero in upon these numbers specifically.
steve